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BROWNINGS CHILDE
06-16-2009, 08:35 PM
IF:
20(1ST) = 1(18TH ) = 1(7TH) = 5(1ST)

AND:
100(18TH ) = 1(1ST) = 25(7TH)

THEN:
1 = ?
18 = ?
7 = ?

John_and_Yoko
06-16-2009, 09:19 PM
IF:
20(1) = 1(18 ) = 1(7) = 5(1)

AND:
100(18 ) = 1(1) = 25(7)

THEN:
1 = ?
18 = ?
7 = ?

Assuming this is algebra, and you're having actual numbers stand in for letters....

7 must be four times 18, and 1 must be 25 times 7, right?

So say instead of 1, 18, and 7 you substitute A, R, and G.

A=25G=100R

<.<

>.>

Beyond that I'm stumped--I don't know how to make the first one work out.... Unless you're being REALLY tricky and having SOME of those 1's being A's and some actually 1 but you're not saying which is which....

BROWNINGS CHILDE
06-16-2009, 11:22 PM
Assuming that this is straight algebra would be a mistake. Yes the parentheses imply multiplication, However, substituting for variables would be a mistake. I dont want to give away too much yet.

John_and_Yoko
06-16-2009, 11:47 PM
Assuming that this is straight algebra would be a mistake. Yes the parentheses imply multiplication, However, substituting for variables would be a mistake. I dont want to give away too much yet.

Well, then, I have NO idea....

:unsure:

BROWNINGS CHILDE
06-16-2009, 11:55 PM
As a math equation, it obviously doesnt work. So, It probably should not be approached as such.

I may have been too tricky, but I'll will give some further clues as needed.

John_and_Yoko
06-17-2009, 05:12 AM
I tried letters of the alphabet, as well as Roman numerals, and neither of those work....

Maturins_Daughter
06-17-2009, 08:42 AM
Color me clueless, man... :scared:

educatedlady
06-17-2009, 09:52 AM
This makes my brain hurt :pullhair:

BROWNINGS CHILDE
06-17-2009, 05:44 PM
I have edited the original to hopefully help out.

Jon
06-18-2009, 03:55 AM
IF:
20(1ST) = 1(18TH ) = 1(7TH) = 5(1ST)

AND:
100(18TH ) = 1(1ST) = 25(7TH)

THEN:
1 = ?
18 = ?
7 = ?



Just givin' this a shot.

THEN:
1 = first
18 = eighteenth
7 = seventh

BROWNINGS CHILDE
06-18-2009, 04:43 PM
1st,18th,and 7th obviously imply that there is an order to the answers. Perhaps chronological....

Another clue: This riddle may be more difficult for Non-American members...say sorry

John_and_Yoko
06-18-2009, 05:36 PM
IF:
20(1ST) = 1(18TH ) = 1(7TH) = 5(1ST)

AND:
100(18TH ) = 1(1ST) = 25(7TH)

THEN:
1 = ?
18 = ?
7 = ?

D'oh! :doh:

1 = George Washington?
7 = Andrew Jackson?
18 = Ulysses S. Grant?

But that doesn't make sense....

BROWNINGS CHILDE
06-18-2009, 06:29 PM
Doh!:doh:

I made a stupid. Indeed, Grant is the 18th president. If one substitutes, 16th for 18th, maybe the riddle will make more sense.

I gave too much away on my previous clue it seems.

Good job J and Y.

John_and_Yoko
06-18-2009, 08:57 PM
Doh!:doh:

I made a stupid. Indeed, Grant is the 18th president. If one substitutes, 16th for 18th, maybe the riddle will make more sense.

I gave too much away on my previous clue it seems.

Good job J and Y.

That would be Abraham Lincoln, but it still doesn't make perfect sense.... Because where does Andrew Jackson fit in?

BROWNINGS CHILDE
06-18-2009, 09:43 PM
Andrew Jackson is on the 20 dollar bill.
George Washington is on the one dollar bill and on the quarter.
Abe Lincoln is on the penny and the 5 dollar bill.

Thus:
--------------------------------------------------------------------------------

20(1ST) (20$ or 5$)= 1(16TH ) (5$) = 1(7TH) (20$) = 5(1ST) (5$)

100(16TH ) (1$ or 500$) = 1(1ST) (1$) = 25(7TH) (500$)

I dont think that this was a very good riddle, even if it hadnt been flawed by my mistake.

John_and_Yoko
06-18-2009, 09:45 PM
Andrew Jackson is on the 20 dollar bill.
George Washington is on the one dollar bill and on the quarter.
Abe Lincoln is on the penny and the 5 dollar bill.

Thus:
--------------------------------------------------------------------------------

20(1ST) (20$ or 5$)= 1(16TH ) (5$) = 1(7TH) (20$) = 5(1ST) (5$)

100(16TH ) (1$ or 500$) = 1(1ST) (1$) = 25(7TH) (500$)

I dont think that this was a very good riddle, even if it hadnt been flawed by my mistake.

Ah, okay, I see what you did there....

It wasn't a bad riddle, barring your mistake--and I might have seen it if it had been a president who ISN'T on our currency. :)

No one's gotten MY riddle yet, at any rate.... :(

Jon
06-18-2009, 11:08 PM
I appreciate your effort BC! I was just put off by the algebraic look to the riddle.

Me+Algebra= clusterfuck!